A good answer might be:

There are two objects, each with a unique reference. There are two reference variables, each containing a different reference.

Equality of Reference Variable Contents

The == operator looks at the contents of two reference variables. If the contents of both reference variables is the same, then the result is true. Otherwise the result is false. Since each object has a unique reference, the operator determines if two reference variables refer to the same object.

The == operator does NOT look at objects!   It only looks at references (information about where an object is located.)

Here is a section from the previous program, with an additional if statement:


    String strA;  // reference to the first object
    String strB;  // reference to the second object
     
    strA   = new String( "The Gingham Dog" );    // create the first object and  
                                                 // save its reference
    System.out.println( strA ); 

    strB   = new String( "The Calico Cat" );     // create the second object and
                                                 // save its reference
    System.out.println( strB );

    if ( strA == strB ) 
      System.out.println( "This will not print.");

Since the reference in strA is different than the reference in strB,

strA == strB

is false. (Look at the picture on the previous page.) The third output statement will not execute.

QUESTION 13:

Did the == operator look at the contents of the objects when the if statement executed?